HRID362723

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID313

Hydrochloric Acid

ClH

HCID4875

Potassium iodide

HCID96387

4-Phenylpiperidin-4-ol

C11H15NO

结构：CS(=O)(=O)OCCCC1(c2ccc(Cl)c(Cl)c2)COC(=O)N(Cc2ccccc2)C1

HCID15886679

未命名化合物

PRODUCTS

生成物

结构：Cl.Cl.O.O=C1OCC(CCCN2CCC(O)(c3ccccc3)CC2)(c2ccc(Cl)c(Cl)c2)CN1Cc1ccccc1.O=C1OCC(CCCN2CCC(O)(c3ccccc3)CC2)(c2ccc(Cl)c(Cl)c2)CN1Cc1ccccc1

HCID131720056

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID3283

Diethyl Ether

C4H10O

溶剂HCID6228

N,N-Dimethylformamide

C3H7NO

PROCEDURE

实验过程

This compound is prepared by the procedure described in step D of EXAMPLE 8 from 1.6 g of 4-hydroxy-4-phenylpiperidine, 2 g of the compound obtained in step C of EXAMPLE 8 and 0.75 g of potassium iodide in 10 ml of DMF. The residue is chromatographed on silica H using DCM and then a DCM/MeOH mixture (96/4; v/v) as the eluent. The product obtained is taken up with a saturated solution of gaseous HCl in ether and the precipitate formed is wrung to give 1.34 g of the expected product. M.p.=125° C.

WORKUP

后处理

customThis compound is prepared by the procedure
customThe residue is chromatographed on silica H
customThe product obtained
customthe precipitate formed

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-208a158614374841b6a1caf55f4aaae3
来源数据集: uspto-grants-1999_02
DOI: 10.6084/m9.figshare.5104873.v1
专利: US05869663
来源说明: uspto-grants-1999_02

反应 SMILES

[OH:1][C:2]1([C:8]2[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=2)[CH2:7][CH2:6][NH:5][CH2:4][CH2:3]1.[CH2:14]([N:21]1[CH2:26][C:25]([C:35]2[CH:40]=[CH:39][C:38]([Cl:41])=[C:37]([Cl:42])[CH:36]=2)([CH2:27][CH2:28][CH2:29]OS(C)(=O)=O)[CH2:24][O:23][C:22]1=[O:43])[C:15]1[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=1.[I-].[K+].[ClH:46]>CN(C=O)C.CCOCC>[OH2:1].[ClH:41].[CH2:14]([N:21]1[CH2:26][C:25]([C:35]2[CH:40]=[CH:39][C:38]([Cl:41])=[C:37]([Cl:42])[CH:36]=2)([CH2:27][CH2:28][CH2:29][N:5]2[CH2:6][CH2:7][C:2]([OH:1])([C:8]3[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=3)[CH2:3][CH2:4]2)[CH2:24][O:23][C:22]1=[O:43])[C:15]1[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=1.[CH2:14]([N:21]1[CH2:26][C:25]([CH2:27][CH2:28][CH2:29][N:5]2[CH2:6][CH2:7][C:2]([C:8]3[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=3)([OH:1])[CH2:3][CH2:4]2)([C:35]2[CH:40]=[CH:39][C:38]([Cl:41])=[C:37]([Cl:42])[CH:36]=2)[CH2:24][O:23][C:22]1=[O:43])[C:15]1[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=1.[ClH:46]