1-Pentyn-3-ol → rac-(Z)-1,3-Dihydro-5-fluoro-4-(3-hydroxy-1-pentynyl)-3-[(1H-pyrrol-2-yl)methylene]-2H-indol-2-one

HRID 366697Notes

Reaction equation

HRID 366697 reaction equation
[CH:1]#[C:2][CH:3]([OH:6])[CH2:4][CH3:5].[F:7][C:8]1[C:9](I)=[C:10]2[C:14](=[CH:15][CH:16]=1)[NH:13][C:12](=[O:17])/[C:11]/2=[CH:18]\[C:19]1[NH:20][CH:21]=[CH:22][CH:23]=1>C1C=CC([P]([Pd]([P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)([P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)[P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)=CC=1.CN(C=O)C.CCN(CC)CC>[F:7][C:8]1[C:9]([C:1]#[C:2][CH:3]([OH:6])[CH2:4][CH3:5])=[C:10]2[C:14](=[CH:15][CH:16]=1)[NH:13][C:12](=[O:17])/[C:11]/2=[CH:18]\[C:19]1[NH:20][CH:21]=[CH:22][CH:23]=1

Participants

6

Procedure

Using Method C above, 1-pentyn-3-ol (58.9 mg, 0.7 mmol) (Aldrich) was coupled with (Z)-1,3-dihydro-5-fluoro-4-iodo-3-[(1H-pyrrol-2-yl)methylene]-2H-indol-2-one (100 mg, 0.28 mmol) (Starting Material 5, supra) using (Ph3P)4Pd (32 mg) and Cul (5.3 mg) as catalyst in DMF (5 mL) and Et3N (5 mL) as solvent at 85° C. for 10 h to yield rac-(Z)-1,3-Dihydro-5-fluoro-4-(3-hydroxy-1-pentynyl)-3-[(1H-pyrrol-2-yl)methylene]-2H-indol-2-one. (Yield 64 mg, 70%).

Sources & evidence

ORD record
ord-bb8c10025fb642c1b4ec17da92309a3e
Source dataset
uspto-grants-2000_10
Patent number
US06130239

Reaction notes

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