HRID366710

反应详情

EQUATION

反应方程式

HRID 366710 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

3

PROCEDURE

实验过程

Using Method C above, 4-ethynyl-tetrahydro-pyran-4-ol (43.3 mg, 0.34 mmol) (Example 85A) was coupled with (Z)-1,3-dihydro-4-bromo-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-5-nitro-2H-indol-2-one (50 mg, 0.14 mmol) (Starting Material 7) using (Ph3P)4Pd (16 mg) and Cul (3.0 mg) as catalyst in DMF (4 mL) and Et3N (4 mL) as solvent at 85° C. for 18 h to give (Z)-1,3-Dihydro-4-[(4-hydroxy-tetrahydro-pyran-4-yl)ethynyl]-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-5-nitro-2H-indol-2-one. (Yield 30 mg, 53%).