Sodium hydride → Sodium Hydroxide
Reaction equation
[N+:1]([C:4]1[N:5]=[CH:6][NH:7][CH:8]=1)([O-:3])=[O:2].[H-].[Na+:10].Br[CH:12]([CH2:18][CH2:19][CH2:20][CH2:21][CH2:22][C:23]([F:26])([F:25])[F:24])[C:13]([O:15]CC)=[O:14]>CO>[OH-:2].[Na+:10].[N+:1]([C:4]1[N:5]=[CH:6][N:7]([CH:12]([CH2:18][CH2:19][CH2:20][CH2:21][CH2:22][C:23]([F:24])([F:26])[F:25])[C:13]([OH:15])=[O:14])[CH:8]=1)([O-:3])=[O:2]Participants
6
Reactant 3
Product 2
Reagents, catalysts & solvents 1
Procedure
4-Nitroimidazole (43 mmoles, 4.86 g) was reacted with sodium hydride(43 moles, 1.72 g) and then ethyl 2-bromo-8,8,8-trifluorooctanoate (43 moles, 13.2 g) as in Example 1. The ester was hydrolyzed in 10 ml methanol and 30 ml 2N NaOH to yield a quantitative yield of 2-(4-nitro-1H-imidazol-1-yl)-8,8,8-trifluorooctanoic acid. (NMR)
Sources & evidence
- ORD record
- ord-e08675ddc11a432290e3343317f67b83
- Source dataset
- uspto-grants-1996_01
- Patent number
- US05484780
Reaction notes
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