Lithium hydroxide, monohydrate → (Z)-6-[2,3-dihydro-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2-oxo-1H-indol-4-yl]-5-hexynoic acid

HRID 380814Notes

Reaction equation

HRID 380814 reaction equation
C[O:2][C:3](=[O:27])[CH2:4][CH2:5][CH2:6][C:7]#[C:8][C:9]1[CH:17]=[CH:16][CH:15]=[C:14]2[C:10]=1/[C:11](=[CH:19]/[C:20]1[NH:21][CH:22]=[CH:23][C:24]=1[O:25][CH3:26])/[C:12](=[O:18])[NH:13]2.O[Li].O>C1COCC1.O>[CH3:26][O:25][C:24]1[CH:23]=[CH:22][NH:21][C:20]=1/[CH:19]=[C:11]1\[C:12](=[O:18])[NH:13][C:14]2[C:10]\1=[C:9]([C:8]#[C:7][CH2:6][CH2:5][CH2:4][C:3]([OH:27])=[O:2])[CH:17]=[CH:16][CH:15]=2

Participants

5

Reactant 2

HCID 168937Lithium hydroxide, monohydrateHCID 59959899(Z)-6-[2,3-dihydro-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2-oxo-1H-indol-4-yl]-5-hexynoic acid methyl ester

Product 1

HCID 59959913(Z)-6-[2,3-dihydro-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2-oxo-1H-indol-4-yl]-5-hexynoic acid

Reagents, catalysts & solvents 2

HCID 962WaterSolventHCID 8028TetrahydrofuranSolvent

Procedure

Using Method F above, (Z)-6-[2,3-dihydro-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2-oxo-1H-indol-4-yl]-5-hexynoic acid methyl ester (40 mg, 0.11 mmol) (from Example 7 above) was hydrolyzed with LiOH•H2O (92 mg, 2.19 mmol) in THF (3 mL) and water (3 mL) for 22 h yielding (Z)-6-[2,3-dihydro-3-[(3-methoxy-1H-pyrrol-2-yl)methylene]-2-oxo-1H-indol-4-yl]-5-hexynoic acid. (Yield 31 mg, 81%).

Sources & evidence

ORD record
ord-ab70591f850d4e8bac4620903ed8409f
Source dataset
uspto-grants-2001_10
Patent number
US06303793B1

Reaction notes

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