Lithium Hydroxide → HCID 59615468, compound

HRID 43582Notes

Reaction equation

HRID 43582 reaction equation
[Cl:1][C:2]1[N:3]=[C:4]([C:9]([NH:11][CH:12]2[CH2:20][C:19]3[C:14](=[CH:15][CH:16]=[C:17]([NH:21][C:22]([C@@H:24]4[CH2:26][C@H:25]4[C:27]([O:29]CC)=[O:28])=[O:23])[CH:18]=3)[CH2:13]2)=[O:10])[NH:5][C:6]=1[CH2:7][CH3:8].[OH-].[Li+]>CO>[Cl:1][C:2]1[N:3]=[C:4]([C:9]([NH:11][CH:12]2[CH2:20][C:19]3[C:14](=[CH:15][CH:16]=[C:17]([NH:21][C:22]([C@@H:24]4[CH2:26][C@H:25]4[C:27]([OH:29])=[O:28])=[O:23])[CH:18]=3)[CH2:13]2)=[O:10])[NH:5][C:6]=1[CH2:7][CH3:8]

Participants

4

Reactant 2

HCID 3939Lithium HydroxideHCID 68414544Ethyl trans(+/-)-2-[(2-{[(4-chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}-2,3-dihydro-1H-inden-5-yl)carbamoyl]cyclopropanecarboxylate

Product 1

HCID 59615468HCID 59615468, compoundYield 76%

Reagents, catalysts & solvents 1

HCID 887MethanolSolvent

Procedure

The same operation as in Example (91d) was performed using ethyl trans(±)-2-[(2-{[(4-chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}-2,3-dihydro-1H-inden-5-yl)carbamoyl]cyclopropanecarboxylate obtained in Example (98b) (100 mg, 0.23 mmol), 2 N lithium hydroxide (3 mL, 6 mmol) and methanol (3 mL), to obtain 71 mg of the title compound as a colorless solid (76%).

Sources & evidence

ORD record
ord-42ce4fd76ee0402e97a719680e754654
Source dataset
uspto-grants-2013_09
Patent number
US08536197B2

Reaction notes

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