Lithium Hydroxide → HCID 86648580, compound

HRID 43605Notes

Reaction equation

HRID 43605 reaction equation
[Cl:1][C:2]1[N:3]=[C:4]([C:9]([NH:11][C@H:12]2[CH2:17][CH2:16][N:15]([C:18]3[O:19][CH:20]=[C:21]([C:23]([O:25]CC)=[O:24])[N:22]=3)[CH2:14][C@H:13]2[O:28][CH3:29])=[O:10])[NH:5][C:6]=1[CH2:7][CH3:8].[OH-].[Li+]>CO>[Cl:1][C:2]1[N:3]=[C:4]([C:9]([NH:11][C@H:12]2[CH2:17][CH2:16][N:15]([C:18]3[O:19][CH:20]=[C:21]([C:23]([OH:25])=[O:24])[N:22]=3)[CH2:14][C@H:13]2[O:28][CH3:29])=[O:10])[NH:5][C:6]=1[CH2:7][CH3:8]

Participants

4

Reactant 2

HCID 3939Lithium HydroxideHCID 86648579Ethyl cis(+/-)-2-(4-{[(4-chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}-3-methoxypiperidin-1-yl)-1,3-oxazole-4-carboxylate

Product 1

HCID 86648580HCID 86648580, compoundYield 43%

Reagents, catalysts & solvents 1

HCID 887MethanolSolvent

Procedure

The same operation as in Example (91d) was performed using ethyl cis(±)-2-(4-{[(4-chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}-3-methoxypiperidin-1-yl)-1,3-oxazole-4-carboxylate obtained in Example (103e) (0.19 g, 0.45 mmol), 2 N lithium hydroxide (2 mL, 4 mmol) and methanol (3 mL), to obtain 76 mg of the title compound as a colorless solid (43%).

Sources & evidence

ORD record
ord-527889b1ff6245fa8c083bd8cdc56da5
Source dataset
uspto-grants-2013_09
Patent number
US08536197B2

Reaction notes

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