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HRID46410

反应详情

EQUATION

反应方程式

HRID 46410 的结构方程式

REACTANTS

反应物

2
结构：CCN(CC)CC
HCID8471

Triethylamine

C6H15N

结构：O=S(=O)(CCCl)CC(O)C(O)CS(=O)(=O)CCCl
HCID13469204

1,4-Bis(2-chloroethanesulfonyl)butane-2,3-diol

C8H16Cl2O6S2

PRODUCTS

生成物

1
结构：C=CS(=O)(=O)CC(O)C(O)CS(=O)(=O)C=C
HCID20387005

1,4-Bis(ethenylsulfonyl)-2,3-butanediol

C8H14O6S2

收率 84.7%

AUXILIARIES

试剂、催化剂与溶剂

1
结构：CC(C)=O
溶剂HCID180

Acetone

C3H6O

PROCEDURE

实验过程

11.4 g of 1,4-bis(chloroethylsulfonyl)-2,3-butanediol was dissolved in 300 ml of acetone and the same procedures as described in Synthesis Example 3 were followed using 6.8 g of triethylamine to obtain 7.6 g of white crystals.

WORKUP

后处理

  1. customthe same procedures as described in Synthesis Example 3