HRID471463

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID313

Hydrochloric Acid

ClH

HCID10796

Cesium carbonate

CCs2O3

HCID160439

1,6-Dioxaspiro(2.5)octane

C6H10O2

结构：CCOC(=O)[C@H]1C[C@@H]1c1ccc(O[C@@H]2CCc3c2ccc(C(F)(F)F)c3-c2ccc(O)cc2)cc1

HCID86703894

未命名化合物

PRODUCTS

生成物

结构：CCOC(=O)[C@H]1C[C@@H]1c1ccc(O[C@@H]2CCc3c2ccc(C(F)(F)F)c3-c2ccc(OCC3(O)CCOCC3)cc2)cc1

HCID86703895

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID962

Water

H2O

溶剂HCID6228

N,N-Dimethylformamide

C3H7NO

CONDITIONS

反应条件

温度: 100 °C

PROCEDURE

实验过程

((1S,2S)-2-{4-[(R)-4-(4-Hydroxy-phenyl)-5-trifluoromethyl-indan-1-yloxy]-phenyl}-cyclopro-panecarboxylic acid ethyl ester (crude from step 2), 1,6-dioxa-spiro[2.5]octane (US2012/46304, 44 mg) and cesium carbonate (198 mg) are suspended in dry N,N-dimethylformamide and heated at 100° C. for 3 hours. The mixture is diluted with water, acidified with 0.2 M HCl solution and extracted with ethyl acetate. The combined organic extracts are concentrated under vacuum and the residue purified by flash chromatography (0-30% EtOAc in cyclohexane) ti give the title compound (yield 50 mg).

WORKUP

后处理

extractionextracted with ethyl acetate
concentrationThe combined organic extracts are concentrated under vacuum
customthe residue purified by flash chromatography (0-30% EtOAc in cyclohexane) ti

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-2ef9da7c07234a1bbac33a7b94f0ad9d
来源数据集: uspto-grants-2014_01
DOI: 10.6084/m9.figshare.5104873.v1
专利: US08633182B2
来源说明: uspto-grants-2014_01

反应 SMILES

[CH2:1]([O:3][C:4]([C@H:6]1[CH2:8][C@@H:7]1[C:9]1[CH:14]=[CH:13][C:12]([O:15][C@H:16]2[C:24]3[C:19](=[C:20]([C:29]4[CH:34]=[CH:33][C:32]([OH:35])=[CH:31][CH:30]=4)[C:21]([C:25]([F:28])([F:27])[F:26])=[CH:22][CH:23]=3)[CH2:18][CH2:17]2)=[CH:11][CH:10]=1)=[O:5])[CH3:2].[O:36]1[C:38]2([CH2:43][CH2:42][O:41][CH2:40][CH2:39]2)[CH2:37]1.C(=O)([O-])[O-].[Cs+].[Cs+].Cl>CN(C)C=O.O>[CH2:1]([O:3][C:4]([C@H:6]1[CH2:8][C@@H:7]1[C:9]1[CH:10]=[CH:11][C:12]([O:15][C@H:16]2[C:24]3[C:19](=[C:20]([C:29]4[CH:34]=[CH:33][C:32]([O:35][CH2:37][C:38]5([OH:36])[CH2:43][CH2:42][O:41][CH2:40][CH2:39]5)=[CH:31][CH:30]=4)[C:21]([C:25]([F:26])([F:27])[F:28])=[CH:22][CH:23]=3)[CH2:18][CH2:17]2)=[CH:13][CH:14]=1)=[O:5])[CH3:2]