Hydrochloric Acid → 2-fluoro-3-methylpentanoic acid
Reaction equation
[F:1][CH:2]([CH:8]([CH3:11])[CH2:9][CH3:10])[C:3]([O:5]CC)=[O:4].[OH-].[Na+].Cl>>[F:1][CH:2]([CH:8]([CH3:11])[CH2:9][CH3:10])[C:3]([OH:5])=[O:4]Participants
4
Procedure
To 8.5 g of the compound (iv) was added 1N NaOH aqueous solution, followed by stirring at room temperature for 8 hours. The solution was acidified with dilute hydrochloric acid and then extracted with ether. The extract was freed of ether by distillation. Thus there was obtained 2-fluoro-3-methylpentanoic acid (v).
Workup
- extractionextracted with ether
- distillationThe extract was freed of ether by distillation
Sources & evidence
- ORD record
- ord-3ee9725470c043b7b30ecdb68591553f
- Source dataset
- uspto-grants-1993_07
- Patent number
- US05225105
Reaction notes
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