huagongshe.com
HRID485019

反应详情

EQUATION

反应方程式

HRID 485019 的结构方程式

REACTANTS

反应物

3
结构：O=C(Cl)c1ccccc1
HCID7412

Benzoyl chloride

C7H5ClO

结构：O=C([O-])O.[Na+]
HCID516892

Sodium Bicarbonate

CHNaO3

结构：CC(C)C(=O)CN.Cl
HCID13401736

1-Amino-3-methylbutan-2-one--hydrogen chloride (1/1)

C5H12ClNO

PRODUCTS

生成物

1
结构：CC(C)C(=O)CNC(=O)c1ccccc1
HCID13490305

N-(3-Methyl-2-oxobutyl)benzamide

C12H15NO2

收率 90.5%

PROCEDURE

实验过程

4.5 g of isobutyrylmethylamine hydrochloride, 11 g of sodium bicarbonate and 4.81 g of benzoyl chloride are treated in the same manner as described in Preparation 1-(4). 6.07 g of N-benzoylisobutyrylmethylamine are thereby obtained. Yield: 90.5%.

WORKUP

后处理

  1. customas described in Preparation 1-(4)