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HRID485020

反应详情

EQUATION

反应方程式

HRID 485020 的结构方程式

REACTANTS

反应物

3
结构：CCOC(=O)CBr
HCID7748

Ethyl bromoacetate

C4H7BrO2

结构：[H-].[Na+]
HCID24758

Sodium hydride

HNa

结构：CC(C)C(=O)CNC(=O)c1ccccc1
HCID13490305

N-(3-Methyl-2-oxobutyl)benzamide

C12H15NO2

PRODUCTS

生成物

1
结构：CCOC(=O)CC(NC(=O)c1ccccc1)C(=O)C(C)C
HCID13488802

Ethyl 3-(benzoylamino)-5-methyl-4-oxohexanoate

C16H21NO4

收率 67.8%

PROCEDURE

实验过程

6.8 g of N-benzoylisobutyrylmethylamine, 1.56 g of 61% sodium hydride and 6.1 g of ethyl bromoacetate are treated in the same manner as described in Preparation 1-(5). 6.54 g of ethyl 3-benzoylamino-3-isobutyrylpropionate are thereby obtained. Yield: 67.7%.

WORKUP

后处理

  1. customas described in Preparation 1-(5)