Stannous Chloride → 6-(Trifluoromethoxy)quinolin-8-amine
Reaction equation
[N+:1]([C:4]1[CH:5]=[C:6]([O:15][C:16]([F:19])([F:18])[F:17])[CH:7]=[C:8]2[C:13]=1[NH:12][C:11](=O)[CH:10]=[CH:9]2)([O-])=O.[Sn](Cl)Cl>Cl>[F:19][C:16]([F:17])([F:18])[O:15][C:6]1[CH:7]=[C:8]2[C:13](=[C:4]([NH2:1])[CH:5]=1)[N:12]=[CH:11][CH:10]=[CH:9]2Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
In a similar fashion using route 1 general procedure 4, 8-nitro-6-(trifluoromethoxy)quinolone (Intermediate 34) (1.1 g, 4.26 mmol), tin (II) chloride (2.42 g, 12.8 mmol) and 6 N HCl (13 drops) gave the title compound (820 mg, 84%) which was used in the next step without purification.
Sources & evidence
- ORD record
- ord-21318f5fd3394da6869a56505f1ad65e
- Source dataset
- uspto-grants-2015_08
- Patent number
- US09102688B2
Reaction notes
Loading…