Stannous Chloride → 5-Fluoroquinolin-8-amine
Reaction equation
[F:1][C:2]1[CH:11]=[CH:10][C:9]([N+:12]([O-])=O)=[C:8]2[C:3]=1[CH:4]=[CH:5][CH:6]=[N:7]2.[Sn](Cl)Cl>Cl>[F:1][C:2]1[CH:11]=[CH:10][C:9]([NH2:12])=[C:8]2[C:3]=1[CH:4]=[CH:5][CH:6]=[N:7]2Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
In a similar fashion using route 1 general procedure 4, 5-fluoro-8-nitroquinoline (Intermediate 38) (500 mg, 2.60 mmol), tin (II) chloride (1.48 mg, 7.80 mmol) and 6N HCl (4 drops) gave the title compound (450 mg, >100% crude) which was used in the next step without purification. The structure was confirmed by 1H NMR.
Sources & evidence
- ORD record
- ord-298ae85fea2e40198d3e3363f146e7b2
- Source dataset
- uspto-grants-2015_08
- Patent number
- US09102688B2
Reaction notes
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