1-Bromo-4-fluorobenzene → (4-Chloro-3-fluorophenyl)(4-fluorophenyl)methanol

HRID 561500Notes

Reaction equation

HRID 561500 reaction equation
[F:1][C:2]1[CH:7]=[CH:6][C:5](Br)=[CH:4][CH:3]=1.[F:9][C:10]1[CH:11]=[C:12]([CH:15]=[CH:16][C:17]=1[Cl:18])[CH:13]=[O:14].ClC1C=CC(C(C2C=CC(OC)=CC=2)O)=CC=1>>[Cl:18][C:17]1[CH:16]=[CH:15][C:12]([CH:13]([C:5]2[CH:6]=[CH:7][C:2]([F:1])=[CH:3][CH:4]=2)[OH:14])=[CH:11][C:10]=1[F:9]

Participants

4

Reactant 3

HCID 99931-Bromo-4-fluorobenzeneHCID 27249854-Chloro-3-FluorobenzaldehydeHCID 2757631(4-Chlorophenyl)(4-methoxyphenyl)methanol

Product 1

HCID 2757452(4-Chloro-3-fluorophenyl)(4-fluorophenyl)methanol

Procedure

The title compound was prepared starting from 5.00 g (28.57 mmol) of 4-fluorobromobenzene and 5.44 g (34.29 mmol) of 3-fluoro-4-chlorobenzaldehyde in analogy to the synthesis of the compound from Example 175A. 5.01 g (69% of theory) of the title compound were obtained.

Workup

  1. customThe title compound was prepared

Sources & evidence

ORD record
ord-07e23b0d43db4bc6ba9eaeaef5352827
Source dataset
uspto-grants-2011_11
Patent number
US08063234B2

Reaction notes

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