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HRID590566

反应详情

EQUATION

反应方程式

HRID 590566 的结构方程式

REACTANTS

反应物

4
结构：CCOC(=O)CC(C)=O
HCID8868

Ethyl acetoacetate

C6H10O3

结构：O=Cc1ccc(F)cc1Cl
HCID145024

2-Chloro-4-fluorobenzaldehyde

C7H4ClFO

结构：O=Cc1cccc(F)c1Cl
HCID14944905

2-Chloro-3-fluorobenzaldehyde

C7H4ClFO

结构：COC(=O)C1=C(CBr)NC(c2nccs2)=N[C@H]1c1ccc(F)cc1Cl
HCID89995948

未命名化合物

PRODUCTS

生成物

1
结构：CCOC(=O)C1=C(CBr)NC(c2nccs2)=N[C@H]1c1cccc(F)c1Cl
HCID118358749

未命名化合物

PROCEDURE

实验过程

Compound C-1 was prepared in analogy to compound C by using ethyl acetoacetate and 2-chloro-3-fluorobenzaldehyde instead of methyl acetoacetate and 2-chloro-4-fluorobenzaldehyde.