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HRID605235

反应详情

EQUATION

反应方程式

HRID 605235 的结构方程式

REACTANTS

反应物

2
结构：Nc1ccc(C(F)(F)F)cn1
HCID735862

5-(trifluoromethyl)pyridin-2-amine

C6H5F3N2

结构：O=C(Cl)c1ccc(F)c([N+](=O)[O-])c1
HCID2783347

4-fluoro-3-nitrobenzoyl chloride

C7H3ClFNO3

PRODUCTS

生成物

1
结构：O=C(Nc1ccc(C(F)(F)F)cn1)c1ccc(F)c([N+](=O)[O-])c1
HCID67040536

未命名化合物

收率 100%

PROCEDURE

实验过程

The product from Example 172a was reacted with 5-trifluoromethyl-pyridin-2-ylamine (239 mg, 1.474 mmol) according to the procedure from Example 172b to provide the title compound (485 mg, 100%).