Sodium hydride → HCID 178462379, compound

HRID 60536Notes

Reaction equation

HRID 60536 reaction equation
[H-].[Na+].[BH4-].[Na+].O.[NH2:6][C:7]1[N:12]=[C:11]([SH:13])[N:10]=[C:9]([OH:14])[CH:8]=1.Cl[C@@H:16]([C:18]1[CH:23]=[CH:22][CH:21]=[CH:20][C:19]=1[F:24])[CH3:17]>CN(C=O)C>[NH2:6][C:7]1[N:12]=[C:11]([S:13][C@H:16]([C:18]2[CH:23]=[CH:22][CH:21]=[CH:20][C:19]=2[F:24])[CH3:17])[N:10]=[C:9]([OH:14])[CH:8]=1

Participants

6

Procedure

NaH (60% in oil, 1.05 g, 26.3 mmol) was added in portions followed by NaBH4 (0.099 g, 2.7 mmol) to 6-amino-2-mercaptopyrimidin-4-ol monohydrate (4.23 g, 26.3 mmol) in DMF (40 mL). After 30 minutes, 1-[(1R)-1-chloroethyl]-2-fluorobenzene (5.0 g, 31.5 mmol) in DMF (10 mL) was added and the reaction mixture was stirred for 24 h. The reaction mixture was concentrated and partitioned between water and DCM, the organic phase was dried (MgSO4) and evaporated. The residue was purified by flash column chromatography (a stepwise gradient of 5-10% MeOH in CHCl3) to give the title compound (5.20 g, 75% yield).

Workup

  1. concentrationThe reaction mixture was concentrated
  2. custompartitioned between water and DCM
  3. dry with materialthe organic phase was dried (MgSO4)
  4. customevaporated
  5. customThe residue was purified by flash column chromatography (a stepwise gradient of 5-10% MeOH in CHCl3)

Sources & evidence

ORD record
ord-dffca4060c9b4372a3edffb642c3f6b7
Source dataset
uspto-grants-2016_09
Patent number
US09440992B2

Reaction notes

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