Phenol → Catechol

HRID 616068Notes

Reaction equation

[C:1]1([OH:7])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.S([O-])([O-])(=O)=[O:9].[In+3].S([O-])([O-])(=O)=[O:15].S([O-])([O-])(=O)=O.[In+3]>>[C:1]1([C:6](=[CH:5][CH:4]=[CH:3][CH:2]=1)[OH:9])[OH:7].[C:1]1([CH:6]=[CH:5][C:4]([OH:15])=[CH:3][CH:2]=1)[OH:7]

Participants

Reactant 2

HCID 996Phenol

HCID 26044Indium sulfate

Product 2

HCID 289Catechol

HCID 785Hydroquinone

Procedure

With 10 g. (106 m.moles) of phenol was admixed the ketone peroxide as listed in Table 3 so that a peroxide amount (P) may be 5.30. To the mixture was added 0.70 g. of indium sulfate (In2 (SO4)3.9H2O) and then the reaction was carried out at 100° C. for 30 minutes. Yields of catechol and hydroquinone are shown in Table 3.

Workup

additionTo the mixture was added 0.70 g

Sources & evidence

ORD record: ord-fa4b626ea2564711bb4625659d041bb5
Source dataset: uspto-grants-1978_02
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US04072722

Reaction notes

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