HRID625339

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID81531

Diisopropylethylamine

C8H19N

HCID7058074

(+)-1,2,3,4-Tetrahydro-1-naphthylamine

C10H13N

结构：CN(C)C(On1nnc2cccnc21)=[N+](C)C.F[P-](F)(F)(F)(F)F

HCID9886157

Methanaminium, N-((dimethylamino)(3H-1,2,3-triazolo(4,5-b)pyridin-3-yloxy)methylene)-N-methyl-, hexafluorophosphate(1-) (1:1)

C10H15F6N6OP

结构：CN(CCN1CCOCC1)C(=O)c1cccc(C(=O)Nc2ccc(N3CCCCC3)cc2-c2cc(C(=O)O)ccn2)c1

HCID66588049

未命名化合物

PRODUCTS

生成物

结构：CN(CCN1CCOCC1)C(=O)c1cccc(C(=O)Nc2ccc(N3CCCCC3)cc2-c2cc(C(=O)N[C@H]3CCCc4ccccc43)ccn2)c1

HCID66588048

未命名化合物

收率 32.6%

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID6228

N,N-Dimethylformamide

C3H7NO

PROCEDURE

实验过程

A solution of 550 mg of 2-(2-(3-(methyl(2-morpholinoethyl)carbamoyl)benzamido)-5-(piperidin-1-yl)phenyl)isonicotinic acid, 142 mg of (S)-1,2,3,4-tetrahydronaphthalen-1-amine, and 497 mg of diisopropylethylamine in 6 mL of DMF was treated with 366 mg of HATU. After stirring for 2 h the product was isolated by reverse phase HPLC, eluting with 0.05% TFA in a water/acetonitrile gradient. The procedure gave 220 mg of product.

WORKUP

后处理

customwas isolated by reverse phase HPLC
washeluting with 0.05% TFA in a water/acetonitrile gradient

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-73694e4864914b4abc9816a4eb9528ee
来源数据集: uspto-grants-2016_04
DOI: 10.6084/m9.figshare.5104873.v1
专利: US09301951B2
来源说明: uspto-grants-2016_04

反应 SMILES

[CH3:1][N:2]([CH2:35][CH2:36][N:37]1[CH2:42][CH2:41][O:40][CH2:39][CH2:38]1)[C:3]([C:5]1[CH:6]=[C:7]([CH:32]=[CH:33][CH:34]=1)[C:8]([NH:10][C:11]1[CH:16]=[CH:15][C:14]([N:17]2[CH2:22][CH2:21][CH2:20][CH2:19][CH2:18]2)=[CH:13][C:12]=1[C:23]1[CH:24]=[C:25]([CH:29]=[CH:30][N:31]=1)[C:26](O)=[O:27])=[O:9])=[O:4].[C@@H:43]1([NH2:53])[C:52]2[C:47](=[CH:48][CH:49]=[CH:50][CH:51]=2)[CH2:46][CH2:45][CH2:44]1.C(N(C(C)C)CC)(C)C.CN(C(ON1N=NC2C=CC=NC1=2)=[N+](C)C)C.F[P-](F)(F)(F)(F)F>CN(C=O)C>[CH3:1][N:2]([CH2:35][CH2:36][N:37]1[CH2:38][CH2:39][O:40][CH2:41][CH2:42]1)[C:3](=[O:4])[C:5]1[CH:34]=[CH:33][CH:32]=[C:7]([C:8]([NH:10][C:11]2[CH:16]=[CH:15][C:14]([N:17]3[CH2:18][CH2:19][CH2:20][CH2:21][CH2:22]3)=[CH:13][C:12]=2[C:23]2[CH:24]=[C:25]([C:26](=[O:27])[NH:53][C@@H:43]3[C:52]4[C:47](=[CH:48][CH:49]=[CH:50][CH:51]=4)[CH2:46][CH2:45][CH2:44]3)[CH:29]=[CH:30][N:31]=2)=[O:9])[CH:6]=1