HRID65498

反应详情

EQUATION

反应方程式

HRID 65498 的结构方程式

CONDITIONS

反应条件

温度
50 °C

PROCEDURE

实验过程

In a 100 ml apparatus, there were combined 11.6 g (0.1 mol) of Et3SiH, 11.5 g (0.1 mol) of MeSiHCl2, and 9.1 g (0.1 mol) of methallyl chloride. After heating to 50° C., the heat source was removed and 0.05 ml Pt catalyst solution added, causing an exothermic reaction to 83.5° C. in 4 min. The complete reaction was vacuum distilled, yielding 13.83 g (67.3%) of MeSiCl2CH2CHMeCH2Cl and 4.31 g (20.9%) of Et3SiCH2CHMeCH2Cl. This example shows that while MeSiHCl2 at the equimolar level promotes the reaction between Et3SiH and methallyl chloride, it also competes with Et3SiH, reducing the yield of Et3SiCH2CHMeCH2Cl.

WORKUP

后处理

  1. customthe heat source was removed
  2. addition0.05 ml Pt catalyst solution added
  3. customan exothermic reaction to 83.5° C. in 4 min
  4. customThe complete reaction
  5. distillationdistilled