HRID661292

反应详情

EQUATION

反应方程式

HRID 661292 的结构方程式

PROCEDURE

实验过程

60.0 mg (0.116 mmol) of the compound from Example 42 were reacted according to General Method 2 with 36.1 mg (0.105 mmol) of meta-chloroperbenzoic acid. Enantiomer separation of the racemate according to Method 2D gave 10.0 mg of the title compound of Example 43 (enantiomer 1).

WORKUP

后处理

  1. customEnantiomer separation of the racemate