HRID661301

反应详情

EQUATION

反应方程式

HRID 661301 的结构方程式

PROCEDURE

实验过程

129 mg (0.266 mmol) of the compound from Example 64 were reacted according to General Method 2 with 82.7 mg (0.240 mmol) of meta-chloroperbenzoic acid. Enantiomer separation of 132 mg of the racemate according to Method 8D gave 51.0 mg of the title compound from Example 65 (enantiomer 1) and 53.0 mg of the title compound from Example 66 (enantiomer 2).

WORKUP

后处理

  1. customEnantiomer separation of 132 mg of the racemate