HRID70941

反应详情

EQUATION

反应方程式

HRID 70941 的结构方程式

REACTANTS

反应物

2

结构：O=C(Cl)C(=O)Cl

Ethanedioyl dichloride

C2Cl2O2

结构：O=C(O)c1ccc(Oc2ccccc2)cc1

Benzoic acid, 4-phenoxy-

C13H10O3

PRODUCTS

生成物

1

结构：O=C(Cl)c1ccc(Oc2ccccc2)cc1

Benzoyl chloride, 4-phenoxy-

C13H9ClO2

PROCEDURE

实验过程

4-Phenoxybenzoyl chloride was prepared by reacting 4-phenoxybenzoic acid with oxalyl chloride.