Lithium Hydroxide → HCID 68816288, compound
Reaction equation
C[O:2][C:3](=[O:26])[C:4]1[CH:16]=[C:15]([C:17]([F:25])([F:24])[C:18]2[CH:23]=[CH:22][CH:21]=[CH:20][CH:19]=2)[CH:14]=[C:6]([C:7]([N:9]([CH3:13])[CH2:10][CH2:11][CH3:12])=[O:8])[CH:5]=1.[OH-].[Li+]>C1COCC1>[F:24][C:17]([F:25])([C:18]1[CH:19]=[CH:20][CH:21]=[CH:22][CH:23]=1)[C:15]1[CH:14]=[C:6]([C:7]([N:9]([CH3:13])[CH2:10][CH2:11][CH3:12])=[O:8])[CH:5]=[C:4]([CH:16]=1)[C:3]([OH:26])=[O:2]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
Chill a solution of 5-(difluorophenyl-methyl)-N-methyl-N-propyl-isophthalamic acid methyl ester (0.043 g, 0.119 mmol) in THF (1 mL) in an ice bath. Add 1 N lithium hydroxide (0.18 mL, 0.18 mmol) and stir at room temperature for 3 h. Acidify the solution to about pH=2 and concentrate to one half of the solvent. Partition the residue between ethyl acetate and H2O. Extract the aqueous layer with ethyl acetate (2×10 mL). Wash the combined organic extract with saturated aqueous sodium chloride, dry (magnesium sulfate) and concentrate to give the title compound (95%).
Workup
- concentrationconcentrate to one half of the solvent
- customPartition the residue between ethyl acetate and H2O
- extractionExtract the aqueous layer with ethyl acetate (2×10 mL)
- washWash the combined
- extractionorganic extract with saturated aqueous sodium chloride
- dry with materialdry (magnesium sulfate)
- concentrationconcentrate
Sources & evidence
- ORD record
- ord-4794d8e09566494fb3f43fed505b5958
- Source dataset
- uspto-grants-2009_09
- Patent number
- US07585885B2
Reaction notes
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