Hydrochloric Acid → HCID 68519472, compound
Reaction equation
[CH3:1][S:2]([C:5]1[CH:10]=[CH:9][C:8]([C:11]2[C:12]([O:29][C:30]3[CH:35]=[CH:34][C:33]([O:36][CH2:37][CH2:38][N:39]4[CH2:44][CH2:43][CH2:42][CH2:41][CH2:40]4)=[CH:32][CH:31]=3)=[C:13]3[C:18](=[CH:19][CH:20]=2)[CH:17]=[C:16]([O:21][C:22](=[O:28])[O:23][CH2:24][CH:25]([CH3:27])[CH3:26])[CH:15]=[CH:14]3)=[CH:7][CH:6]=1)(=[O:4])=[O:3].[ClH:45].CCOCC>ClCCl>[ClH:45].[CH3:1][S:2]([C:5]1[CH:6]=[CH:7][C:8]([C:11]2[C:12]([O:29][C:30]3[CH:31]=[CH:32][C:33]([O:36][CH2:37][CH2:38][N:39]4[CH2:40][CH2:41][CH2:42][CH2:43][CH2:44]4)=[CH:34][CH:35]=3)=[C:13]3[C:18](=[CH:19][CH:20]=2)[CH:17]=[C:16]([O:21][C:22](=[O:28])[O:23][CH2:24][CH:25]([CH3:26])[CH3:27])[CH:15]=[CH:14]3)=[CH:9][CH:10]=1)(=[O:4])=[O:3]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
Dissolve the compound of Example 9 (104 mg, 0.17 mmol) in dichloromethane (3 mL) and add 2M HCl in ether (400 μL, 0.8 mmol). Remove the solvent in vacuo to yield 81 mg of the title compound (73%): mass spectrum (ion spray): m/z=618.3 (M+H−HCl).
Workup
- customRemove the solvent in vacuo
Sources & evidence
- ORD record
- ord-87e18fcbeae14fb7826d31649a26233c
- Source dataset
- uspto-grants-2009_09
- Patent number
- US07585977B2
Reaction notes
Loading…