HRID735545

反应详情

EQUATION

反应方程式

HRID 735545 的结构方程式

PROCEDURE

实验过程

Using a procedure analogous to that described for the preparation of 16G, 21B (0.700 g, 1.25 mmol) was reacted with mCPBA (0.695 g, 3.10 mmol) to give 21C (0.513 g, 69%). MS (ESI) m/z 595, 597.4 (M+H)+.