Hydrochloric Acid → HCID 68517807, compound

HRID 748886Notes

Reaction equation

HRID 748886 reaction equation
[N:1]1([CH2:7][CH2:8][O:9][C:10]2[CH:40]=[CH:39][C:13]([O:14][C:15]3[C:24]([C:25]4[CH:30]=[CH:29][C:28]([S:31]([C:34]([F:37])([F:36])[F:35])(=[O:33])=[O:32])=[CH:27][CH:26]=4)=[CH:23][CH:22]=[C:21]4[C:16]=3[CH:17]=[CH:18][C:19]([OH:38])=[CH:20]4)=[CH:12][CH:11]=2)[CH2:6][CH2:5][CH2:4][CH2:3][CH2:2]1.[ClH:41]>C(OCC)(=O)C.C(OCC)C>[ClH:41].[N:1]1([CH2:7][CH2:8][O:9][C:10]2[CH:40]=[CH:39][C:13]([O:14][C:15]3[C:24]([C:25]4[CH:30]=[CH:29][C:28]([S:31]([C:34]([F:35])([F:36])[F:37])(=[O:32])=[O:33])=[CH:27][CH:26]=4)=[CH:23][CH:22]=[C:21]4[C:16]=3[CH:17]=[CH:18][C:19]([OH:38])=[CH:20]4)=[CH:12][CH:11]=2)[CH2:6][CH2:5][CH2:4][CH2:3][CH2:2]1

Participants

5

Reactant 2

HCID 313Hydrochloric AcidHCID 10053779HCID 10053779, compound

Product 1

HCID 68517807HCID 68517807, compoundYield 47%

Reagents, catalysts & solvents 2

HCID 3283Diethyl EtherSolvent2×HCID 8857Ethyl AcetateSolvent

Procedure

Dissolve the compound of Example 20 (196 mg, 0.34 mmol) in ethyl acetate (1 mL) and diethyl ether (9 mL). Add 2M HCl in diethyl ether (340 μl, 680 μmol) to the stirred solution. Allow the suspension to stir for 10 minutes. Filter the solids through a Buchner funnel. Dry the solids overnight at 45° C. in a vacuum oven to yield 98 mg of the title compound (47%): mass spectrum (ion spray) m/z=572.3 (M+H—HCl).

Workup

  1. filtrationFilter the solids through a Buchner funnel
  2. customDry the solids overnight at 45° C. in a vacuum oven

Sources & evidence

ORD record
ord-accd22e776ff4a9994af6fbff5c4103e
Source dataset
uspto-grants-2008_07
Patent number
US07399867B2

Reaction notes

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