2-Fluoroethyl bromide → HCID 22234989, compound

HRID 749558Notes

Reaction equation

HRID 749558 reaction equation
[N+:1]([C:4]1[CH:15]=[CH:14][C:7]([CH2:8][CH:9]([C:12]#[N:13])[C:10]#[N:11])=[CH:6][CH:5]=1)([O-:3])=[O:2].[H-].[Na+].Br[CH2:19][CH2:20][F:21]>CN(C)C=O>[N+:1]([C:4]1[CH:5]=[CH:6][C:7]([CH2:8][C:9]([CH2:19][CH2:20][F:21])([C:10]#[N:11])[C:12]#[N:13])=[CH:14][CH:15]=1)([O-:3])=[O:2]

Participants

5

Reactant 3

HCID 129822-Fluoroethyl bromideHCID 24758Sodium hydrideHCID 27641462-(4-nitrobenzyl)malononitrile

Product 1

HCID 22234989HCID 22234989, compoundYield 22%

Reagents, catalysts & solvents 1

HCID 6228DimethylformamideSolvent

Procedure

Using 0.40 g of (4-nitrobenzyl)malononitrile, 5 ml of N,N-dimethylformamide, 0.12 g of sodium hydride (60% in oil), and 0.25 g of 1-bromo-2-fluoroethane, and according to the process described in the Production Example 1, there was obtained 0.10 g of 2-(4-nitrobenzyl)-2-(2-fluoroethyl)malononitrile (the present compound (47)).

Sources & evidence

ORD record
ord-ca72fe5d5ce74794aee9b21e3a1f4e62
Source dataset
uspto-grants-2008_07
Patent number
US07402691B2

Reaction notes

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