2-Fluoroethyl bromide → HCID 22235015, compound

HRID 749573Notes

Reaction equation

HRID 749573 reaction equation
[Br:1][C:2]1[CH:3]=[C:4]([CH:11]=[CH:12][CH:13]=1)[CH2:5][CH:6]([C:9]#[N:10])[C:7]#[N:8].[H-].[Na+].Br[CH2:17][CH2:18][F:19]>CN(C)C=O>[Br:1][C:2]1[CH:3]=[C:4]([CH:11]=[CH:12][CH:13]=1)[CH2:5][C:6]([CH2:17][CH2:18][F:19])([C:7]#[N:8])[C:9]#[N:10]

Participants

5

Reactant 3

HCID 129822-Fluoroethyl bromideHCID 24758Sodium hydrideHCID 22235058HCID 22235058, compound

Product 1

HCID 22235015HCID 22235015, compoundYield 38.3%

Reagents, catalysts & solvents 1

HCID 6228DimethylformamideSolvent

Procedure

Using 0.24 g of (3-bromobenzyl)malononitrile, 3 ml of N,N-dimethylformamide, 0.10 g of sodium hydride (60% in oil), and 0.13 g of 1-bromo-2-fluoroethane, and according to the process described in the Production Example 1, there was obtained 0.11 g of 2-(3-bromobenzyl)-2-(2-fluoroethyl)malononitrile (the present compound (65)).

Sources & evidence

ORD record
ord-359499d1790d4d0b8547b89c33bbbc3d
Source dataset
uspto-grants-2008_07
Patent number
US07402691B2

Reaction notes

Loading…