2-Fluoroethyl bromide → HCID 22234981, compound

HRID 749575Notes

Reaction equation

HRID 749575 reaction equation
[Br:1][C:2]1[CH:13]=[CH:12][C:5]([CH2:6][CH:7]([C:10]#[N:11])[C:8]#[N:9])=[C:4]([F:14])[CH:3]=1.[H-].[Na+].Br[CH2:18][CH2:19][F:20]>CN(C)C=O>[Br:1][C:2]1[CH:13]=[CH:12][C:5]([CH2:6][C:7]([CH2:18][CH2:19][F:20])([C:8]#[N:9])[C:10]#[N:11])=[C:4]([F:14])[CH:3]=1

Participants

5

Reactant 3

HCID 129822-Fluoroethyl bromideHCID 24758Sodium hydrideHCID 22235010HCID 22235010, compound

Product 1

HCID 22234981HCID 22234981, compoundYield 33.8%

Reagents, catalysts & solvents 1

HCID 6228DimethylformamideSolvent

Procedure

Using 0.25 g of (4-bromo-2-fluorobenzyl)malononitrile, 3 ml of N,N-dimethylformamide, 0.10 g of sodium hydride (60% in oil), and 0.13 g of 1-bromo-2-fluoroethane, and according to the process described in the Production Example 1, there was obtained 0.10 g of 2-(4-bromo-2-fluorobenzyl)-2-(2-fluoroethyl)malononitrile (the present compound (67)).

Sources & evidence

ORD record
ord-43169e988d37453c86192a889aa1fb7a
Source dataset
uspto-grants-2008_07
Patent number
US07402691B2

Reaction notes

Loading…