Phosphorus oxide (P4O10) → Stannic chloride pentahydrate

HRID 864882Notes

Reaction equation

HRID 864882 reaction equation
[O:1]=P12OP3(OP(OP(O3)(O1)=O)(=O)O2)=O.[Cl:15][Sn:16]([Cl:19])([Cl:18])[Cl:17]>O.Cl>[Sn:16]([Cl:19])([Cl:18])([Cl:17])[Cl:15].[OH2:1].[OH2:1].[OH2:1].[OH2:1].[OH2:1]

Participants

5

Reactant 2

HCID 14812Phosphorus oxide (P4O10)2×HCID 24287Tin tetrachloride2×

Product 1

HCID 61442Stannic chloride pentahydrate

Reagents, catalysts & solvents 2

HCID 313Hydrochloric AcidSolvent3×HCID 962WaterSolvent2×

Procedure

Approximately 2000 ml of distilled water was heated to about 80 degrees C. A solution of SnCl4.5H2O in 500 ml of distilled water, 0.445 g SnO2 /ml was prepared. Approximately 52.5 g of P2O5 was dissolved in 440 ml of concentrated HCl, then an additional 217 ml of HCl was added. About 500 ml of concentrated HCl was added to the SnCl4 solution. The SnCl4 and P2O5 solutions were mixed together in a beaker.

Sources & evidence

ORD record
ord-e6e4a5563ab34040aa18d53fec0146fb
Source dataset
uspto-grants-1996_10
Patent number
US05565144

Reaction notes

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