Phosphorus oxide (P4O10) → Stannic chloride pentahydrate

HRID 864883Notes

Reaction equation

HRID 864883 reaction equation
[O:1]=P12OP3(OP(OP(O3)(O1)=O)(=O)O2)=O.[Cl:15][Sn:16]([Cl:19])([Cl:18])[Cl:17]>Cl.O>[Sn:16]([Cl:19])([Cl:18])([Cl:17])[Cl:15].[OH2:1].[OH2:1].[OH2:1].[OH2:1].[OH2:1]

Participants

5

Reactant 2

HCID 14812Phosphorus oxide (P4O10)2×HCID 24287Tin tetrachloride

Product 1

HCID 61442Stannic chloride pentahydrate

Reagents, catalysts & solvents 2

HCID 313Hydrochloric AcidSolvent3×HCID 962WaterSolvent2×

Procedure

Approximately 6500 ml of distilled water was heated to about 80 degrees C. Approximately 30 g of P2O5 was dissolved in 250 ml of concentrated HCl, then an additional 125 ml of HCl was added. A solution of SnCl4.5H2O in 2000 ml of distilled water was prepared which contained about 0.445 g SnO2 /ml. A solution of TaCl5 in concentrated HCl was prepared which contained about 0.19M TaCl5. The TaCl5, SnCl4 and P2O5 solutions were mixed together in a beaker.

Sources & evidence

ORD record
ord-27e657ca08f24478909b6b93ef7bf95a
Source dataset
uspto-grants-1996_10
Patent number
US05565144

Reaction notes

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