Phosphorus oxide (P4O10) → Stannic chloride pentahydrate

HRID 865900Notes

Reaction equation

HRID 865900 reaction equation
[O:1]=P12OP3(OP(OP(O3)(O1)=O)(=O)O2)=O.[Cl:15][Sn:16]([Cl:19])([Cl:18])[Cl:17]>Cl.O>[Sn:16]([Cl:19])([Cl:18])([Cl:17])[Cl:15].[OH2:1].[OH2:1].[OH2:1].[OH2:1].[OH2:1]

Participants

5

Reactant 2

HCID 14812Phosphorus oxide (P4O10)2×HCID 24287Tin tetrachloride

Product 1

HCID 61442Stannic chloride pentahydrate

Reagents, catalysts & solvents 2

HCID 313Hydrochloric AcidSolvent3×HCID 962WaterSolvent2×

Procedure

Approximately 6500 ml of distilled water was heated to about 80 degrees C. Approximately 30 g of P2O5 was dissolved in 250 ml of concentrated HCl, then an additional 125 ml of HCl was added. A solution of SnCl4.5H2O in 2000 ml of distilled water was prepared which contained about 0.445 g SnO2 /ml. A solution of TaCl5 in concentrated HCl was prepared which contained about 0.19 M TaCl5 . The TaCl5 , SnCl4 and P2O5 solutions were mixed together in a beaker.

Sources & evidence

ORD record
ord-8ae3f3714f4442ada4f8fb24846540b3
Source dataset
uspto-grants-1996_10
Patent number
US05569412

Reaction notes

Loading…