Tetrabutylammonium Fluoride → HCID 66563827, compound

HRID 901978Notes

Reaction equation

HRID 901978 reaction equation
[Si]([O:8][CH2:9][CH2:10][O:11][CH2:12][CH:13]1[CH2:18][CH2:17][N:16]([C:19]([O:21][CH2:22][C:23]2[CH:28]=[CH:27][CH:26]=[CH:25][CH:24]=2)=[O:20])[CH2:15][CH2:14]1)(C(C)(C)C)(C)C.[F-].C([N+](CCCC)(CCCC)CCCC)CCC>O1CCCC1>[OH:8][CH2:9][CH2:10][O:11][CH2:12][CH:13]1[CH2:18][CH2:17][N:16]([C:19]([O:21][CH2:22][C:23]2[CH:28]=[CH:27][CH:26]=[CH:25][CH:24]=2)=[O:20])[CH2:15][CH2:14]1

Participants

4

Reactant 2

HCID 2724141Tetrabutylammonium FluorideHCID 69313202HCID 69313202, compound

Product 1

HCID 66563827HCID 66563827, compoundYield 78.2%

Reagents, catalysts & solvents 1

HCID 8028TetrahydrofuranSolvent

Procedure

The reaction was carried out in similar procedure to Example 75b using 237 mg (0.58 mmol) of benzyl 4-[(2-{[tert-butyl(dimethyl)silyl]oxy}ethoxy)methyl]piperidine-1-carboxylate obtained in Example 77a and 0.87 mL (0.87 mmol) of a solution of 1M tetrabutylammonium fluoride in tetrahydrofuran to obtain 133 mg (yield: 78%) of the title compound as a brown oil.

Sources & evidence

ORD record
ord-52282a8da9544eaea4f9c381dea684a3
Source dataset
uspto-grants-2008_04
Patent number
US07365067B2

Reaction notes

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