Lithium Hydroxide → HCID 11555958, compound

HRID 905624Notes

Reaction equation

HRID 905624 reaction equation
[NH2:1][C:2]1[N:10]=[C:9]([O:11][CH2:12][CH2:13][CH2:14][CH3:15])[N:8]=[C:7]2[C:3]=1[NH:4][C:5](=[O:40])[N:6]2[CH2:16][CH2:17][CH2:18][CH2:19][N:20]([CH2:35][C@@H:36]([OH:39])[CH2:37][OH:38])[S:21]([C:24]1[CH:25]=[C:26]([CH2:30][C:31]([O:33]C)=[O:32])[CH:27]=[CH:28][CH:29]=1)(=[O:23])=[O:22].[OH-].[Li+].O1CCCC1>O>[NH2:1][C:2]1[N:10]=[C:9]([O:11][CH2:12][CH2:13][CH2:14][CH3:15])[N:8]=[C:7]2[C:3]=1[NH:4][C:5](=[O:40])[N:6]2[CH2:16][CH2:17][CH2:18][CH2:19][N:20]([CH2:35][C@@H:36]([OH:39])[CH2:37][OH:38])[S:21]([C:24]1[CH:25]=[C:26]([CH2:30][C:31]([OH:33])=[O:32])[CH:27]=[CH:28][CH:29]=1)(=[O:22])=[O:23]

Participants

5

Reactant 3

HCID 3939Lithium HydroxideHCID 8028TetrahydrofuranHCID 11621196HCID 11621196, compound

Product 1

HCID 11555958HCID 11555958, compound

Reagents, catalysts & solvents 1

HCID 962WaterSolvent

Procedure

The compound obtained in Example 2-25 (100 mg) and lithium hydroxide (20 mg) were added to tetrahydrofuran (5 ml) and water (2 ml), and the same manner to Example 2-12 was conducted to give the titled compound as a white solid. Yield: 58 mg (60%); MS APCI+ve 567 (M+H).

Sources & evidence

ORD record
ord-54ba747ad398491996b75da8a25f6085
Source dataset
uspto-grants-2011_09
Patent number
US08012964B2

Reaction notes

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