Lithium Hydroxide → HCID 11692648, compound

HRID 905625Notes

Reaction equation

HRID 905625 reaction equation
[NH2:1][C:2]1[N:10]=[C:9]([O:11][CH2:12][CH2:13][CH2:14][CH3:15])[N:8]=[C:7]2[C:3]=1[NH:4][C:5](=[O:42])[N:6]2[CH2:16][CH2:17][CH2:18][CH2:19][N:20]([CH2:30][C:31]1[CH:32]=[C:33]([CH2:37][C:38]([O:40]C)=[O:39])[CH:34]=[CH:35][CH:36]=1)[CH2:21][CH2:22][CH2:23][N:24]1[CH2:29][CH2:28][O:27][CH2:26][CH2:25]1.[OH-].[Li+].O1CCCC1>O>[NH2:1][C:2]1[N:10]=[C:9]([O:11][CH2:12][CH2:13][CH2:14][CH3:15])[N:8]=[C:7]2[C:3]=1[NH:4][C:5](=[O:42])[N:6]2[CH2:16][CH2:17][CH2:18][CH2:19][N:20]([CH2:30][C:31]1[CH:32]=[C:33]([CH2:37][C:38]([OH:40])=[O:39])[CH:34]=[CH:35][CH:36]=1)[CH2:21][CH2:22][CH2:23][N:24]1[CH2:25][CH2:26][O:27][CH2:28][CH2:29]1

Participants

5

Reactant 3

HCID 3939Lithium HydroxideHCID 8028TetrahydrofuranHCID 11570593HCID 11570593, compound

Product 1

HCID 11692648HCID 11692648, compound

Reagents, catalysts & solvents 1

HCID 962WaterSolvent

Procedure

The compound obtained in Example 2-29 (200 mg) and lithium hydroxide (100 mg) were added to tetrahydrofuran (15 ml) and water (5 ml) and the same manner as Example 2-12 was conducted to give the titled compound as a white solid. Yield: 130 mg (66%); MS APCI+ve 570 (M+H).

Sources & evidence

ORD record
ord-060c4fa5c95e45419f762781c669fa1d
Source dataset
uspto-grants-2011_09
Patent number
US08012964B2

Reaction notes

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