Ethyl Bromide → 5-(4-Ethoxy-5-iodo-2-isopropyl-phenoxy)-pyrimidine-2,4-diamine

HRID 925182Notes

Reaction equation

HRID 925182 reaction equation
[NH2:1][C:2]1[N:7]=[C:6]([NH2:8])[C:5]([O:9][C:10]2[C:15]([CH:16]([CH3:18])[CH3:17])=[CH:14][C:13]([OH:19])=[C:12]([I:20])[CH:11]=2)=[CH:4][N:3]=1.[CH2:21](Br)[CH3:22]>CN(C=O)C>[CH2:21]([O:19][C:13]1[C:12]([I:20])=[CH:11][C:10]([O:9][C:5]2[C:6]([NH2:8])=[N:7][C:2]([NH2:1])=[N:3][CH:4]=2)=[C:15]([CH:16]([CH3:18])[CH3:17])[CH:14]=1)[CH3:22]

Participants

4

Reactant 2

HCID 6332Ethyl BromideHCID 159538644-(2,4-Diamino-pyrimidin-5-yloxy)-2-iodo-5-isopropyl-phenol

Product 1

HCID 573296125-(4-Ethoxy-5-iodo-2-isopropyl-phenoxy)-pyrimidine-2,4-diamineYield 78.9%

Reagents, catalysts & solvents 1

HCID 6228DimethylformamideSolvent

Procedure

To a solution of 4-(2,4-Diamino-pyrimidin-5-yloxy)-2-iodo-5-isopropyl-phenol (0.2 g, 0.52 mmol) in anhydrous DMF (2 ml) was added EtBr (57 mg, 0.52 mmol) in portions. The reaction mixture was partitioned between EtOAc and H2O. The organic extract was dried over Na2SO4, filtered and concentrated. Flash chromatography on silica (3% MeOH in methylene chloride with 1% NH4OH) gave 5-(4-Ethoxy-5-iodo-2-isopropyl-phenoxy)-pyrimidine-2,4-diamine (0.17 g, 28%) as a yellow solid. (M+H)=415.

Workup

  1. customThe reaction mixture was partitioned between EtOAc and H2O
  2. extractionThe organic extract
  3. dry with materialwas dried over Na2SO4
  4. filtrationfiltered
  5. concentrationconcentrated

Sources & evidence

ORD record
ord-e27da22cc03442d0b67c2d3e651f1dd8
Source dataset
uspto-grants-2016_03
Patent number
US09284279B2

Reaction notes

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