Phenothiazine → Ethylbenzene
Reaction equation
[CH2:1]=[CH:2][C:3]1[CH:8]=[CH:7][CH:6]=[CH:5][CH:4]=1.C1C2NC3C(=CC=CC=3)SC=2C=CC=1>C1(C)C(C)=CC=CC=1>[CH2:1]=[CH:2][C:3]1[CH:8]=[CH:7][CH:6]=[CH:5][CH:4]=1.[CH2:2]([C:3]1[CH:8]=[CH:7][CH:6]=[CH:5][CH:4]=1)[CH3:1]Participants
5
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 125 °C
Procedure
To a 45 cc high pressure bomb was added 3.75 g (0.0025 mol) Me3SiO(Me2SiO)13.5 (MeSiO)5.5 SiMe3, 5.26 g (0.05 mol) styrene, 2.0 g xylene and 1000 ppm (8.1 mg) Ru3CO12 as a catalsyt. Phenothiazine (75.6 mg) was also added to help prevent polymerization of the styrene. The bomb was then heated in a fluidized sand bath at 125° C. for 10 hours after which time the reaction was cooled to room temperature. The solvent and excess styrene as well as ethylbenzene formed during the course of the reaction was removed under vacuum. Analysis by 1HNMR showed the product to be ##STR10##
Workup
- additionTo a 45 cc high pressure bomb was added 3.75 g (0.0025 mol) Me3SiO(Me2SiO)13
- temperaturewas cooled to room temperature
Sources & evidence
- ORD record
- ord-9279d8c6cbc54d179610057d98d04ade
- Source dataset
- uspto-grants-1987_05
- Patent number
- US04668812
Reaction notes
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