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Lithium hydroxide, monohydrate → HCID 178524335, compound

HRID 1455367
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Reaction equation

HRID 1455367 reaction equation
C(CC[N:5]1[C:9]([C:10]2[CH:11]=[C:12]([CH:17]=[CH:18][CH:19]=2)[C:13]([O:15]C)=[O:14])=[N:8][N:7]=[N:6]1)#N.O.[OH-].[Li+]>C1COCC1.O.Cl>[NH:8]1[C:9]([C:10]2[CH:11]=[C:12]([CH:17]=[CH:18][CH:19]=2)[C:13]([OH:15])=[O:14])=[N:5][N:6]=[N:7]1
ParticipantsProcedureWorkupSources & evidenceReaction notes

Participants

6

Reactant 2

HCID 168937Lithium hydroxide, monohydrateHCID 21075151methyl 3-(1-(2-cyanoethyl)-1H-tetrazol-5-yl)benzoate

Product 1

HCID 178524335HCID 178524335, compoundYield 75.1%

Reagents, catalysts & solvents 3

HCID 313Hydrochloric AcidSolventHCID 962WaterSolvent
HCID 8028
Tetrahydrofuran
Solvent

Procedure

Preparation H7, Step 3: To a solution of methyl 3-(1-(2-cyanoethyl)-1H-tetrazol-5-yl)benzoate (180 mg, 0.7 mmol) in 20 mL of THF cooled to 0° C. was added dropwise a solution of lithium hydroxide monohydrate (50 mg, 2.1 mmol) in 5.0 mL of water. The reaction mixture was stirred at RT for 16 h. THF was removed under reduced pressure to give a yellow oil which was diluted with 10 mL of 1 N HCl. The aqueous phase was extracted with EtOAc (2×25 mL), and the extracts were combined, dried over Na2SO4, and concentrated to afford 100 mg (58% yield) of 3-(1H-tetrazol-5-yl)benzoic acid. MS found: (M+H)+=191.

Workup

  1. customPreparation H7, Step 3
  2. customTHF was removed under reduced pressure
  3. customto give a yellow oil which
  4. extractionThe aqueous phase was extracted with EtOAc (2×25 mL)
  5. dry with materialdried over Na2SO4
  6. concentrationconcentrated

Sources & evidence

ORD record
ord-5596ebd7739b4c0bbf7b53f180513881
Source dataset
uspto-grants-2009_01
DOI
10.6084/m9.figshare.5104873.v1
Patent number
US07482335B2

Reaction notes

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On this pageParticipantsProcedureWorkupSources & evidenceReaction notes