Biphenyl → Biphenyl

HRID 50152

Reaction equation

HRID 50152 reaction equation
[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=2)=[CH:4][CH:3]=1.[C:14]1([C:20]2[CH:25]=[CH:24][CH:23]=[CH:22][CH:21]=2)[CH:19]=[CH:18][CH:17]=[CH:16][CH:15]=1.[Cl:26]Cl>ClC1C=CC=CC=1.[Fe]>[Cl:1][C:2]1[CH:3]=[CH:4][C:5]([C:8]2[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=2)=[CH:6][CH:7]=1.[Cl:1][C:16]1[CH:15]=[C:14]([C:20]2[CH:21]=[CH:22][CH:23]=[CH:24][CH:25]=2)[CH:19]=[CH:18][CH:17]=1.[Cl:26][C:6]1[CH:7]=[CH:2][CH:3]=[CH:4][C:5]=1[C:8]1[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=1.[C:5]1([C:8]2[CH:9]=[CH:10][CH:11]=[CH:12][CH:13]=2)[CH:6]=[CH:7][CH:2]=[CH:3][CH:4]=1

Participants

9

Procedure

It would be desirable to be able to prepare 4-chlorobiphenyl in a single step from biphenyl and chlorine. According to U.S. Pat. No. 1,890,427, this is possible by chlorination of biphenyl in chlorobenzene in the presence of metallic iron as catalyst. However, this gives a mixture comprising 4-chlorobiphenyl, 3-chlorobiphenyl, 2-chlorobiphenyl and unreacted biphenyl. The separation of this mixture is very complicated. For separating off one isomer, the reference describes crystallization from noneutectic mixtures above the freezing point of the eutectic. This means that separation of the entire mixture makes it necessary to carry out a complicated sequence of distillation and crystallization steps. Czech. Chem. Prum., 30(10), 529-32 (1980) confirms this. To achieve purities of greater than 99%, the latter reference describes the following steps to be carried out in succession for the separation of mixtures comprising 2-, 3- and 4-chlorobiphenyl: 1. distillation, 2. crystallization of the fractions from the distillation and 3. recrystallization of the fractions from the crystallization from ethanol.

Sources & evidence

ORD record
ord-ae882cb1dfff490a8f85983c7aca00aa
Source dataset
uspto-grants-2004_03
Patent number
US06710217B1

Linked notes

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