[O:1]1CCCO[CH:2]1[CH2:7][CH2:8][CH2:9][C:10]1[CH:11]=[N:12][CH:13]=[CH:14][CH:15]=1.C([O-])(O)=O.[Na+]>C1COCC1.Cl>[CH:14]1[CH:13]=[N:12][CH:11]=[C:10]([CH2:9][CH2:8][CH2:7][CH:2]=[O:1])[CH:15]=1A solution of 1.5 g (7.8 mmol) of acetal 157 in 10.0 mL of THF and 10.0 mL of 4N HCl was stirred overnight at room temperature and was then neutralized by the slow addition of solid NaHCO3. The reaction mixture was extracted with ethyl acetate, dried over MgSO4 and concentrated to yield 1.1 g of the aldehyde 158. 1H NMR consistent with structure.
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