Hydroquinone → Triphenylmethyl acrylate
Reaction equation
[C:1]1([C:7]([C:15]2[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=2)([C:9]2[CH:14]=[CH:13][CH:12]=[CH:11][CH:10]=2)Cl)[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.[C:21]([O-:25])(=[O:24])[CH:22]=[CH2:23].[K+].C1(C=CC(O)=CC=1)O>CN(C)C=O>[C:21]([O:25][C:7]([C:15]1[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=1)([C:9]1[CH:14]=[CH:13][CH:12]=[CH:11][CH:10]=1)[C:1]1[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1)(=[O:24])[CH:22]=[CH2:23]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
1 mole triphenylchloromethane was stirred with 1.5 moles potassium acrylate in 998 g dimethyl formamide in the presence of 0.14 g hydroquinone under the conditions described in Example 1. The precipitated potassium chloride was filtered off and the triphenyl methyl acrylate solution was concentrated by rotary evaporation at 65° to 100° C. and reduced to produce liquid triphenylmethyl acrylate. This was dissolved at 70 percent in xylene and filtered.