[Br:1][C:2]1[CH:7]=[CH:6][C:5]([SH:8])=[CH:4][CH:3]=1.[H-].[Na+].Br[CH:12]([CH3:14])[CH3:13].O>CN(C)C=O>[Br:1][C:2]1[CH:7]=[CH:6][C:5]([S:8][CH:12]([CH3:14])[CH3:13])=[CH:4][CH:3]=1Dissolve 4-bromo-benzenethiol (1.0 g, 5.3 mmol) in dry dimethylformamide (50 mL) and cool to 0° C. under nitrogen. Add dry sodium hydride (153 mg, 6.4 mmol) in portions. After the vigorous gas evolution stops, add 2-bromo-propane (0.60 mL, 6.4 mmol) and stir the reaction overnight at room temperature. Slowly pour the reaction into water (300 mL) and extract with ethyl acetate (2×150 mL). Wash the combined organic layers with water (100 mL) and brine (100 mL). Dry the organic layer with sodium sulfate, filter and concentrate in vacuo. Chromatograph the resultant residue on a SiO2 column with 5% ethyl acetate in hexanes to yield 1.1 g of 1-bromo-4-isopropylsulfanyl-benzene (92%).
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