Trisodium Phosphate → Tricalcium Phosphate

Reaction equation

[P:1]([O-:5])([O-:4])([O-:3])=[O:2].[Na+].[Na+].[Na+].[Cl-].[Ca+2:10].[Cl-]>O>[P:1]([O-:5])([O-:4])([O-:3])=[O:2].[Ca+2:10].[Ca+2:10].[Ca+2:10].[P:1]([O-:5])([O-:4])([O-:3])=[O:2]

Participants

Procedure

78.6 Grams of sodium phosphate were dissolved in 300 grams of water. In a separate beaker, 45.3 grams of calcium chloride were dissolved in 300 grams of water. 200 Grams of each of the above solutions were added simultaneously to 200 grams of water, while being sheared at speeds of 12,000 rpm. This shearing was necessary, since the viscosity resulting from the in situ formation of tricalcium phosphate (TCP) particulates needs to be to be broken down into submicron size in order to be effective as a stabilizer. The amount of in situ TCP generated in this Example was 21.3 grams