[C:1]1([CH2:7][C:8](=O)[C:9]([O-:11])=[O:10])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.[Na+].[CH:14]1[N:15]=C(N)C2N=CN([C@@H]3O[C@H](COP(OP(OC[C@H]4O[C@@H](N5C=C(C(N)=O)CC=C5)[C@H](O)[C@@H]4O)(O)=O)(O)=O)[C@@H](O)[C@H]3OP(O)(O)=O)C=2N=1.O=C[C@@H]([C@H]([C@@H]([C@@H](CO)O)O)O)O.CN.S(=O)(=O)(O)O.[OH-].[Na+]>>[CH3:14][NH:15][C@H:8]([C:9]([OH:11])=[O:10])[CH2:7][C:1]1[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1In a 50-mL beaker, 5.88 ml of 40 mM Tris-hydrochloride buffer (pH 8.0) containing 60 mg of sodium phenylpyruvate, 2.3 mg of NADPH, 35 U of glucose dehydrogenase, and 1 g of glucose was placed, to which 5.88 mL of 240 mM methylamine adjusted to pH 8.0 with sulfuric acid and 3.25 mL of the above cell-free extract were added, and the mixture was allowed to react at 30° C. The reaction was conducted while stirring and adjusting pH to 8.0 with 1 N aqueous sodium hydroxide solution. A portion of the reaction solution was analyzed by HPLC at regular intervals. When the substrate sodium phenylpyruvate was depleted, an additional 30 mg was added and the reaction was continued. This process was repeated 8 times during the reaction of 24 hours. Upon completion of the reaction, the amount of N-methylphenylalanine produced was 146 mg.
読み込み中…
