Methyl iodide → HCID 59639574、化合物

HRID 556586ノート

反応式

HRID 556586 の反応式
[F:1][C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=1[C:8]1[C:9]2[CH:19]=[CH:18][C:17](=[O:20])[NH:16][C:10]=2[N:11]=[C:12]([S:14][CH3:15])[N:13]=1.[H-].[Na+].I[CH3:24]>C1COCC1>[F:1][C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=1[C:8]1[C:9]2[CH:19]=[CH:18][C:17](=[O:20])[N:16]([CH3:24])[C:10]=2[N:11]=[C:12]([S:14][CH3:15])[N:13]=1

参加物

5

反応物 3

HCID 6328Methyl iodideHCID 24758Sodium hydrideHCID 59639533HCID 59639533、化合物

生成物 1

HCID 59639574HCID 59639574、化合物収率 92%

試薬・触媒・溶媒 1

HCID 8028Tetrahydrofuran溶媒

実験手順

To a solution of 4-(2-fluoro-phenyl)-2-methylsulfanyl-8H-pyrido[2,3-d]pyrimidin-7-one (120 mg, 0.42 mmol) in 20 mL of anhyd THF was added NaH (50 mg, 1.2 mmol, 60% dispersion in mineral oil, 3 eq) followed by iodomethane (74 μL, 1.2 mmol, 3 eq). The reaction mixture was stirred 1 h at 23°, quenched with saturated aq NH4Cl. (20 mL), Et2O (100 mL) was added and the layers were separated. The organic layer was washed with satd aq NaCl, dried (MgSO4), filtered and evaporated. The yellow residue was then purified by Flash chromatography to afford 100 mg (92% yield) of 4-(2-Fluoro-phenyl)-8-methyl-2-methylsulfanyl-8H-pyrido[2,3-d]pyrimidin-7-one. 1H-NMR δ 2.68 (s, 3H), 3.81 (s, 3H), 6.61 (d, 1H, J=9.8 Hz), 7.22 (m, 3H), 7.50 (m, 3H). LC MS (m/e)=302 (MH+). Rt=2.17 min.

後処理

  1. customquenched with saturated aq NH4Cl
  2. addition(20 mL), Et2O (100 mL) was added
  3. customthe layers were separated
  4. washThe organic layer was washed with satd aq NaCl
  5. dry with materialdried (MgSO4)
  6. filtrationfiltered
  7. customevaporated
  8. customThe yellow residue was then purified by Flash chromatography

出典と根拠

ORDレコード
ord-de1c2720fb454a92a1d2339e511bb0a8
出典データセット
uspto-grants-2011_11
特許番号
US08058282B2

反応ノート

読み込み中…