Iodoethane → N-Ethylphenothiazine

HRID 6577

反応式

HRID 6577 の反応式
[CH:1]1[C:14]2[NH:13][C:12]3[C:7](=[CH:8][CH:9]=[CH:10][CH:11]=3)[S:6][C:5]=2[CH:4]=[CH:3][CH:2]=1.I[CH2:16][CH3:17].[OH-].[K+]>S([O-])(O)(=O)=O.C([N+](CCCC)(CCCC)CCCC)CCC.C1(C)C=CC=CC=1>[CH2:16]([N:13]1[C:14]2[CH:1]=[CH:2][CH:3]=[CH:4][C:5]=2[S:6][C:7]2[C:12]1=[CH:11][CH:10]=[CH:9][CH:8]=2)[CH3:17]

参加物

6

実験手順

A mixture of 10 g (0.05 mol) of phenothiazine, 11.7 g (0.075 mol) of iodoethane, 4.2 g (0.075 mol) of potassium hydroxide and 0.25 g of tetra-n-butylammonium hydrogen sulfate in 200 ml of dry toluene was refluxed for 24 hours. After cooling, the reaction mixture was filtered, and the solvent was evaporated. The product was crystallized from methanol. The yield of 10-ethylphenothiazine (C14H13NS, FW=227.33) was 90%.

後処理

  1. temperaturewas refluxed for 24 hours
  2. temperatureAfter cooling
  3. filtrationthe reaction mixture was filtered
  4. customthe solvent was evaporated
  5. customThe product was crystallized from methanol

出典と根拠

ORDレコード
ord-625c6e1d30dd4d0a9f0e4279bcd0f5ff
出典データセット
uspto-grants-2006_08
特許番号
US07083884B2

関連ノート

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