Hydrogen Bromide → 1,7,13-Triazatridecane Trihydrochloride

반응식

Br.C1(C)C=C(C)C=C(C)C=1S([N:13]([CH2:20][CH2:21][CH2:22][CH2:23][CH2:24][NH2:25])[CH2:14][CH2:15][CH2:16][CH2:17][CH2:18][NH2:19])(=O)=O.C1(O)C=CC=CC=1.C(Cl)(Cl)[Cl:35]>>[ClH:35].[ClH:35].[ClH:35].[NH2:25][CH2:24][CH2:23][CH2:22][CH2:21][CH2:20][NH:13][CH2:14][CH2:15][CH2:16][CH2:17][CH2:18][NH2:19]

참가 물질

반응물 4

HCID 260Hydrogen Bromide

HCID 996Phenol

HCID 6212Chloroform

HCID 107853557-Mesitylenesulfonyl-1,7,13-triazatridecane

생성물 1

HCID 219966591,7,13-Triazatridecane Trihydrochloride

실험 절차

HBr (30% in HOAc, 26 mL), 42 (2.0 g, 5.42 mmol), and phenol (4.8 g, 51 mmol) in CHCl3 (40 mL) were reacted, and product was isolated by the method of 2 to give 0.97 (61%) of 24 as a white solid: NMR (D2O) δ 1.45 (m, 4 H), 1.70 (m, 8 H), 3.01 (m, 8 H). Anal. (C10H28Cl3N3) C, H, N.