Hydrochloric Acid → Indenol

HRID 2260021

반응식

HRID 2260021 반응식
[C:1]1(=[O:10])[C:9]2[C:4](=[CH:5][CH:6]=[CH:7][CH:8]=2)[CH:3]=[CH:2]1.[BH4-].[Na+].[Cl-].[Ce+3].[Cl-].[Cl-].Cl>CO.O>[CH:1]1([OH:10])[C:9]2[C:4](=[CH:5][CH:6]=[CH:7][CH:8]=2)[CH:3]=[CH:2]1

참가 물질

7

반응물 4

HCID 313Hydrochloric AcidHCID 24636Cerium(III) chlorideHCID 4311764Sodium borohydrideHCID 118153841H-inden-1-one

생성물 1

HCID 316919Indenol수율 99%

시약·촉매·용매 2

HCID 887Methanol용매HCID 962Water용매

실험 절차

The indenone from Example 109 (0.5 g) is reduced with NaBH4 (0.05 g) and cerium chloride (0.5 g) in methanol (20 ml). The reaction in ended after 10 minutes and the reaction mixture is poured into water. The pH is taken to 5 by means of dilute HCl and the mixture is extracted with ethyl acetate. It is washed with water and the solvent is evaporated. Indenol (0.49 g; m.p. 134° C.) is obtained (yield: 99%; compound no. 110).

후처리

  1. customThe reaction
  2. extractionthe mixture is extracted with ethyl acetate
  3. washIt is washed with water
  4. customthe solvent is evaporated

출처 및 근거

ORD 기록
ord-8715c1e83d4b4fa1bfc24d12c01a77fc
출처 데이터셋
uspto-grants-1995_12
특허 번호
US05475132

연결된 노트

불러오는 중…